Sunday, 18 August 2019

fibonocci series- program

/*ratio of consecutive terms of fibonocci series*/

#include<stdio.h>

#include<math.h>

void

main()

{

int i,f[100];

float r0,r1;

i=0;

f[0]=1;

f[1]=1;

r1=1;

label:

r0=r1;

i++;

f[i+1]=f[i]+f[(i-1)];

r1=f[i+1]/f[i];

if(fabs(r1-r0)>0.001)

goto label;

printf("the value of the ratio is %f\n",r1);

}

RESULT:

enter the number n=10

1.000000 1.0000002.000000

3.000000

5.000000

8.000000

13.000000

21.000000

34.000000

55.000000

s=1.617647

Press any key to continue

Trace of a matrix - C program

/*trace of a matrix*/

#include<stdio.h>

#include<math.h>

void

main()

{

int i,j,a[20][20];

float s=0.0;

printf("enter the elements of input matrix:");

for(i=0;i<2;i++)

{

for(j=0;j<2;j++)

scanf("%d",&a[i][j]);

}

printf("the input matrix is:");

printf("\n");

for(i=0;i<2;i++)

{

for(j=0;j<2;j++)

printf("%d\t",a[i][j]);

printf("\n");

}

for(i=0;i<2;i++)

{

for(j=0;j<2;j++)

{

if(i==j)

s=s+a[i][j];

}

printf("\n the trace is=%f\n",s);

}

RESULT:

enter the elements of input matrix:1 2 3 4

the input matrix is:

1 2

3 4

the trace is=5.000000

Press any key to continue

C program for calculation of mean, median, mode

/*calculation of mean,median,mode*/

#include<stdio.h>

void

main()

{

int i,j,n;

float a[100],t,sum=0.0,mean,median,mode;

printf("enter the total number of data");

scanf("%d",&n);

printf("type the input data:\n");

for(i=0;i<n;i++)

{

scanf("%f",&a[i]);

sum=sum+a[i];

}

mean=sum/n;

printf("mean=%f\n",mean);

/*sorting array*/

for(j=0;j<n;j++)

{

for(i=0;i<n;i++)

{

if(a[i]>a[j])

{t=a[i];

a[i]=a[j];

a[j]=t;

}

if(n%2==0)

median=(a[n/2]+a[(n-2)/2])/2;

else

median=a[(n-1)/2];

mode=(3*median)-(2*mean);

printf("median=%f\n",median);

printf("mode=%f\n",mode);

}

RESULT1:

enter the total number of data3

type the input data:

mean=2.666667

median=3.000000

mode=3.666667

Press any key to continue

RESULT2:

enter the total number of data 10

type the input data:

mean=14.700000

median=5.500000

mode=-12.900000

Press any key to continue

RESULT3:

enter the total number of data6

type the input data:

mean=12.000000

median=10.000000

mode=6.000000

Press any key to continue

Saturday, 17 August 2019

C program for inverse of a matrix

/*Inverse of a matrix*/

#include<stdio.h>

#include<math.h>

void

main()

{

int i,j,det,k,a[20][20];

float I[20][20],U[20][20];

printf("enter the elements of input matrix:");

for(i=0;i<2;i++)

{

for(j=0;j<2;j++)

scanf("%d",&a[i][j]);

}

printf("the input matrix is:");

printf("\n");

for(i=0;i<2;i++)

{

for(j=0;j<2;j++)

printf("%d\t",a[i][j]);

printf("\n");

}

/*matrix determinant*/

det=(a[0][0]*a[1][1])-(a[0][1]*a[1][0]);

printf("\n The determinant is=%d\n",det);

/*matrix inverse*/

if(det==0)

printf("The matrix inverse is not possible:");

else

{

for(i=0;i<2;i++)

{

for(j=0;j<2;j++)

{

if(i==j)

{

I[i][j]=(a[(i+1)%2][(j+1)%2]);

}

else

{

I[i][j]=-(a[i][j]);

}

printf("The inverse matrix is \n");

for(i=0;i<2;i++)

{

for(j=0;j<2;j++)

printf("%.4f\t",(I[i][j]/det));

printf("\n");

}

/*product matrix*/

for(i=0;i<2;i++)

{for(j=0;j<2;j++)

{

U[i][j]=0;

for(k=0;k<2;k++)

U[i][j]=U[i][j]+a[i][k]*I[k][j];

}

printf("\n the product matrix is:\n");

for(i=0;i<2;i++)

{

for(j=0;j<2;j++)

printf("%.4f\t",(U[i][j]/det));

printf("\n");

}

RESULT 1:

enter the elements of input matrix:1 2 3 4

the input matrix is:

1 2

3 4

The determinant is=-2

The inverse matrix is

-2.0000 1.0000

1.5000 -0.5000

the product matrix is:

1.0000 0.0000

0.0000 1.0000

Press any key to continue

RESULT 2:

enter the elements of input matrix:1 1 1 1

the input matrix is:

1 1

The determinant is=0

The matrix inverse is not possible:

Press any key to continue

Solution of quadratic equation C program

/Solution of quadratic equation/

#include<stdio.h>

#include<math.h>

void

main()

{

float a,b,c,d,x1,x2,rp,imp;

printf("enter the value of a,b,c");

scanf("%f%f%f",&a,&b,&c);

d=b*b-4.0*a*c;

if (d>=0)

{

printf("roots are real");

x1=(-b+sqrt(d))/(2.0*a);

x2=(-b-sqrt(d))/(2.0*a);

printf("\n x1= %f,x2= %f\n",x1,x2);

}

else

{

printf("roots are complex");

rp=-b*(2.0*a);

imp=sqrt(abs(d))/(2.0*a);

printf("first root = %f+ %fi\n",rp,imp);

printf("second root= %f-%fi\n",rp,imp);

}

/*Solution of quadratic equation */

#include<stdio.h>

#include<math.h>

void

main()

{

float a,b,c,d,x1,x2,rp,imp;

printf(" enter the value of a,b,c");

scanf("%f%f%f",&a,&b,&c);

d=(b*b)-(4.0*a*c);

if(d>=0)

{

printf("roots are real");

x1=(-b+sqrt(d))/(2.0*a);

x2=(b-sqrt(d))/(2.0*a);

printf("\n x1=%f,x2=%f\n",x1,x2);

}

else

{

printf("roots are complex");

rp=-b/(2.0*a);

imp=sqrt(abs(d))/(2.0*a);

printf("1st root=%f+%fi\n",rp,imp);

printf("2nd root=%f-%fi\n",rp,imp);

}

Result1:

enter the value of a,b,c2 3 1

roots are real

x1=-0.500000,x2=0.500000

Press any key to continue

Result2:

enter the value of a,b,c2 4 2

roots are real

x1=-1.000000,x2=1.000000

Press any key to continue

Result3:

enter the value of a,b,c2 3 5

roots are complex1st root=-0.750000+1.391941i

2nd root=-0.750000-1.391941i

Press any key to continue

Friday, 16 August 2019

Fortran program for celcius to farenheit scale

!program for celcius to farenheit scale

write(*,*)"enter the temperature in celcius scale"

read(*,*)c

f=(9*c)/5 +32

write(*,*)"the temperature in farenheit scale is"

write(*,*)

stop

end

!progrm for sum

read(*,*)a,b,c

y=a+b+c

write(*,*)y

stop

end

! sum for n numbers

read (*,*) n

sum=0

do i=1,n

sum=sum+i

end do

write (*,*) sum

stop

end

!sum of odd numbers

read(*,*)n

x=0

do i=1,n,2

x=x+i

end do

write(*,*)

stop

end

C program for zeta function

/*Zeta function*/

#include<stdio.h>

#include<math.h>

void

main()

{

int i;

float s=0.0,pi,d;

for(i=1;i<=4;i++)

{

s=s+pow(i,-4);

}

d=s*90;

pi=pow(d,0.25);

printf("\n the value of pi is=%f\n",pi);

}

RESULT:

the value of pi is=3.138998

Press any key to continue

C programming for addition, subtraction, multiplication of matrices

/*Addition and subtraction of matrices */

#include<stdio.h>

void

main()

{

int i,j,m,n,a[20][20],b[20][20],c[20][20],d[20][20];

printf("Enter the order of matrices:");

scanf("%d %d",&m,&n);

printf("Enter the element of matrix A:");

for(i=0;i<m;i++)

{

for(j=0;j<n;j++)

scanf("%d",&a[i][j]);

printf("\n");

}

printf("the input matrix A is:\n");

for(i=0;i<m;i++)

{

for(j=0;j<n;j++)

printf("%d\t",a[i][j]);

printf("\n");

}

printf("Enter the element of matrix B:");

for(i=0;i<m;i++)

{

for(j=0;j<n;j++)

scanf("%d",&b[i][j]);

printf("\n");

}

printf("the input matrix B is:\n");

for(i=0;i<m;i++)

{

for(j=0;j<n;j++)

printf("%d\t",b[i][j]);

printf("\n");

}

/*matrix addition*/

for(i=0;i<m;i++)

{

for(j=0;j<n;j++)

c[i][j]=a[i][j]+b[i][j];

}

printf("the summation matrix is:\n");

for(i=0;i<m;i++)

{

for(j=0;j<n;j++)

printf("%d\t",c[i][j]);

printf("\n");

}

/*matrix subtraction*/

for(i=0;i<m;i++)

{

for(j=0;j<n;j++)

d[i][j]=a[i][j]-b[i][j];

}

printf("the summation matrix is:\n");

for(i=0;i<m;i++)

{

for(j=0;j<n;j++)

printf("%d\t",d[i][j]);

printf("\n");

}

RESULT:

Enter the order of matrices:3 3

Enter the element of matrix A:1 2 3 4 5 6 7 8 9

the input matrix A is:

1 2 3

4 5 6

7 8 9

Enter the element of matrix B:12

4 56 11 7 45 0 4 6

the input matrix B is:

12 4 56

11 7 45

0 4 6

the summation matrix is:

13 6 59

15 12 51

7 12 15

the summation matrix is:

-11 -2 -53

-7 -2 -39

7 4 3

Press any key to continue

/*multiplication of matrices*/

#include<stdio.h>

void

main()

{

int i,j,m,n,p,k,a[20][20],b[20][20],c[20][20];

printf("Enter the order of matrix A:");

scanf("%d %d",&m,&n);

printf("Enter the order of matrix B:");

scanf("%d %d",&n,&p);

printf("Enter the element of matrix A:");

for(i=0;i<m;i++)

{

for(j=0;j<n;j++)

scanf("%d",&a[i][j]);

printf("\n");

}

printf("the input matrix A is:\n");

for(i=0;i<m;i++)

{

for(j=0;j<n;j++)

printf("%d\t",a[i][j]);

printf("\n");

}

printf("Enter the element of matrix B:");

for(i=0;i<n;i++)

{

for(j=0;j<p;j++)

scanf("%d",&b[i][j]);

printf("\n");

}

printf("the input matrix B is:\n");

for(i=0;i<n;i++)

{

for(j=0;j<p;j++)

printf("%d\t",b[i][j]);

printf("\n");

}

/*matrix multiplication*/

for(i=0;i<m;i++)

{

for(j=0;j<p;j++)

{

c[i][j]=0;

for(k=0;k<n;k++)

{

c[i][j]=c[i][j]+a[i][k]*b[k][j];

}

printf("the multiplication matrix is :\n");

for(i=0;i<m;i++)

{

for(j=0;j<p;j++)

printf("%d\t",c[i][j]);

printf("\n");

}

RESULT:

Enter the order of matrix A:3 2

Enter the order of matrix B:2 3

Enter the element of matrix A:1 2 3 4 5 6

the input matrix A is:

1 2

3 4

5 6

Enter the element of matrix B:45 65 33 11 0 5

the input matrix B is:

45 65 33

11 0 5

the multiplication matrix is :

67 65 43

179 195 119

291 325 195

Press any key to continue

Sunday, 18 August 2019

Saturday, 17 August 2019

/*Solution of quadratic equation*/

Friday, 16 August 2019

/Solution of quadratic equation/